z^2-3z=3(1-z)-6

Solution for z^2-3z=3(1-z)-6 equation:

Simplifying
z2 + -3z = 3(1 + -1z) + -6

Reorder the terms:
-3z + z2 = 3(1 + -1z) + -6
-3z + z2 = (1 * 3 + -1z * 3) + -6
-3z + z2 = (3 + -3z) + -6

Reorder the terms:
-3z + z2 = 3 + -6 + -3z

Combine like terms: 3 + -6 = -3
-3z + z2 = -3 + -3z

Add '3z' to each side of the equation.
-3z + 3z + z2 = -3 + -3z + 3z

Combine like terms: -3z + 3z = 0
0 + z2 = -3 + -3z + 3z
z2 = -3 + -3z + 3z

Combine like terms: -3z + 3z = 0
z2 = -3 + 0
z2 = -3

Solving
z2 = -3

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Simplifying
z2 = -3

Reorder the terms:
3 + z2 = -3 + 3

Combine like terms: -3 + 3 = 0
3 + z2 = 0

The solution to this equation could not be determined.